PDA

View Full Version : @home to AT&T... good for Canadian users?


XenaRule
10-16-01, 05:33 PM
At least for Rogers... I know Rogers works with AT&T for cell phones, can this be a good thing? :confused: With AT&T, supplying cellphones and internet... what's next? cable tv?? :rotfl:

rodrod5
10-16-01, 09:35 PM
Rogers and Shaw are in the process of dumping @Home entirely

shaw is in the last months of a 2 year project to have their own backbone email content ect. and will be off @Home entirely by the end of the year unless things bog down

Rogers is in the process of deciding if they want to dump @Home for sure now that ATT ..MIGHT.. take them over

if Rogers stays on with ATT is should be as good as it was before if not better down the road

if Rogers goes on its own then i would see short term transition problems in your future

then i would have no idea if it will get better or worse

it took Shaw 2 years of work to pull away from @Home

Rogers does not have that amount of time........if they slap it togather to avoid short term disruptions then you will probably be ok short term and then have problems

if they do it right then you might have short term problems then stable service after the transition;) :rolleyes: :cool: :eek: :2cool: :confused: :sleep: :p

XenaRule
10-17-01, 12:43 AM
Ah, there's something interesting about Shaw that I haven't heard of. I use live in an area where Shaw had provided the cable and internet and then suddenly Rogers took over which really angered me since all the post I've read across the WWW has had bad experience with Rogers. When it did happen... it was ok, some slow down but it was so slightly that you didn't notice. I still think Shaw is a better cable company then Rogers.

A while page someone had told me Rogers were ditching @home but I haven't seen anything since. If this AT&T goes through and Rogers stay, and it DOES benefit us, then great. At least it sounds like there shouldn't be any set back in this.

But if Rogers were to leave @home, which company would they look for?